2x^2-7x-38=8

Solution for 2x^2-7x-38=8 equation:

2x^2-7x-38=8

We move all terms to the left:

2x^2-7x-38-(8)=0

We add all the numbers together, and all the variables

2x^2-7x-46=0

a = 2; b = -7; c = -46;
Δ = b2-4ac
Δ = -72-4·2·(-46)
Δ = 417
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-\sqrt{417}}{2*2}=\frac{7-\sqrt{417}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+\sqrt{417}}{2*2}=\frac{7+\sqrt{417}}{4}
$